A diver is standing on a platform 24ft. Above the pool. He jumps from the platform with an initial upward velocity of 8ft/s. Use the formula h(t)=-16^2+vt+s, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How long will it take for him to hit the water?

Answer:He will take 1.5 seconds to hit the waterStep-by-step explanation:* The formula h(t) = -16t² + vt + s- h is the his height above the water- v is his initial up-word velocity - s is his starting height- t is the time* When he hits the water h(t) = 0 - because h is his height above the water∴ -16t² + vt + s = 0∵ v = 8 ft/s∵ s = 24 ft∴ -16t² + 8t + 24 = 0 ⇒ × (-1)∴ 16t² - 8t - 24 = 0 ⇒ ÷ 8∴ 2t² - t - 3 = 0 ⇒ by using factorization∴ (2t - 3)(t + 1) = 0 ∴ 2t - 3 = 0 ⇒ 2t = 3 ⇒ t = 3/2 = 1.5 sec∴ t + 1 = 0 ⇒ t = -1 ⇒ rejected the time is positive value* He will take 1.5 seconds to hit the water