Can anyone help us solve this problem? a walking trail is 2.9 miles long. if sid walked the length of the walking trail 1 1/3 times. how many miles did sid walk?

ANSWER:  The distance walked by the Sid is 3.87 miles. SOLUTION:   Given, walking trail has a length of 2.9 miles. Sid walked the length of the walking trail [tex]1 \frac{1}{3}[/tex] times.We need to find the distance traveled by Sid in miles. First let's convert the given mixed fraction into improper fraction. [tex]1 \frac{1}{3}=\frac{1 \times 3+1}{3}[/tex][tex]1 \frac{1}{3}=\frac{4}{3}[/tex]Now, the distance walked by Sid = [tex]\frac{4}{3}[/tex] [tex]\times[/tex] length of walking trailDistance walked = [tex]\frac{4}{3} \times 2.9[/tex][tex]=\frac{4 \times 2,9}{3}[/tex][tex]=\frac{11.6}{3}[/tex] = 3.87 milesHence, the distance walked by the Sid is 3.87 miles.