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What is the sum of the arithmetic sequence 153, 139, 125, ..., if there are 22 terms?
4 months ago
Q:
What is the sum of the arithmetic sequence 153, 139, 125, ..., if there are 22 terms?
Accepted Solution
A:
The sum of an Arithmetic series can be calculated as:
[tex] S_{n} = \frac{n}{2}(2 a_{1}+(n-1)*d) [/tex]
n = number of terms = 22
a1 =First Term of the series = 153
d = Common Difference = 139 - 153 = -14
So, using the values, we get:
[tex] S_{22}= \frac{22}{2}(2*153+(22-1)*(-14)) \\ \\ S_{22}=132[/tex]
This means, the sum of first 22 terms of the series will be 132.